brian_griffin
"Eric Cartman?"
I don't believe that is true. If a second (3rd, 4th) lottery is required, all teams from the qualifying round will have equal odds for the pick in question. Overall points percent (including qualifying round - my interpretation) will be used to determine draft order for the non-qualifying teams which don't move up in the 2nd lottery (and 3rd, and 4th, lotteries, if needed) and regular points percentage will be used as a tie-break for the seeding of the non-lottery-winning qualifying round losers.No, the limit of 4 spots of "upward movement" in the draft was one of the concepts they toyed with, but it was dropped. All "lottery teams", ie the top 15, have a chance to win the first overall pick. Or the 2nd or 3rd pick.
The only difference from previous seasons is that after the first 7 teams, ones that are not in the play-in games, are handled like normal but 8 temporary designations (ie Team A, Team B, etc.) will be used to fill in teams 8 thru 15. Once the play-in round of games are completed the 8 teams that lost and fail to advance to the playoffs will be accounted for.
If one of those temporary designations (Team A, Team B, etc) happens to win the 1st, 2nd or 3rd pick then a 2nd lottery will be used to assign the 8 play-in losers to those temporary designations, based on their win % during the regular season. If none of the temp designation teams "wins" a top slot, then there won't be a second lottery and the 8 losing teams will simply be slotted in by their win %.
It sounds much more complicated than it really is.
It's a little more complicated than you proposed. Odds for a 2nd, 3rd, 4th lottery are NOT determined by their points percentage in the regular season, and definitely not by their win percentage, as you noted. Odds in the 2nd (3rd 4th) lottery rounds, if required, are equal for all participating qualifying round losers.
At least that's the way I read it.