KevFu
Registered User
Just checking Kev:
You want to draw 33-48, and make the others go 1/32; 2/31; 3/30, etc???
Would you allow for special provisions so that 3 UEFA nations don't end up grouped together? Or, worse 3 CONCACAF nations?
Yes. You cannot have two teams from the same confederation in the same group. Was that not clear in my original post?
It's pretty simple, you S-Curve based on rankings for 1-32 (after fixing the stupidity of the rankings formula).
So if by the S-Curve you run into this: #13 Italy, #14 USA, #15 Switzerland, #16 Belgium, #17 Ghana, #18 Croatia, #20 Costa Rica, #21 Poland, #22 Ivory Coast
You’d say:
#16 Belgium should be joined by #17 Ghana = Okay.
#15 Switzerland should be joined by #18 Croatia = Not Okay. Croatia must go into the next available pool, against #14 USA.
Next team up is #20 Costa Rica.
#15 Switzerland and #20 Costa Rica = Okay.
#13 Italy should be joined by #21 Poland - Not Okay. Poland must go into the next available pool. #12 is England. #11 is Mexico.
#21 Poland joins #11 Mexico. #22 Ivory Coast will join #13 Italy.
And when you're drawing the teams randomly from the 32-48 pool and it's "Now joining #1 Brazil and #32 Bosnia... (pull) #44 Peru. Peru cannot be placed in the same group as Brazil. Peru will be placed in the next group, joining #2 Germany and #31 Ghana. The next team to join #1 Brazil and #32 Bosnia is... (pull) #46 Japan! This group is #1 Brazil and #32 Bosnia and #44 Japan."
And once the 16 groups have members, you say "USA is the host, so their group of #16 Belgium, #18 USA and #54 Burkino Faso will be Group A. It follows from there that #1 Brazil, #32 Bosnia and #44 Japan are Group B; the #8 seed, #25 seed and the random third team is in Group C; etc.