Lil Sebastian Cossa
Opinions are share are my own personal opinions.
- Jul 6, 2012
- 11,436
- 7,446
Hm. You made me think about it a bit more... I still think that the chances come out the same, since there are still only X valid combinations, and nothing else matters. I suppose the odds would be different where, if we said "On combination two, Detroit still has 8.5% chances", but given that 18.5% or whatever of the combinations don't matter, the fact that it's combination 2 is also irrelevant. The only next combination that matters is the one that's out of 851 or whatever combinations, and so forth (i.e. they could pull 234,897,289 ball combinations and none of them matter a whit if they don't match a valid, remaining combination).
That said, this feels like one of those math problems where my way feels too easy, so...
Either way, sorry tsweeney, if I seemed overly snarky in my response. Wasn't intended personally.
You're good man. I wasn't offended at all. I was saying that on any given pull, the chance that Detroit gets a pick does not change. The overall percentage increases because instead of a void pull ending the selection like a valid one would, they simply re-draw.
Each pull is an individual event with 1000 balls. The fact that 185 of them result in a re-draw may increase the overall percentage chance if one event happens, but for the second pull? The chance is 8.5%. For the third pull? 8.5% If both 2nd and 3rd were void pulls? 8.5%.